MathProblemsBank

10.7.21 Calculating integrals of a real variable using residues

Condition: Using residues, calculate the integral. \[ I_{1}=\int_{0}^{2 \pi}\left(\frac{1}{-6+3 \sin x}+\frac{1}{(6-3 \cos x)^{2}}\right) d x \]

Here you can find calculations of proper and improper integrals of a real variable using residues, using various techniques.

-> Calculating integrals of a real variable using residues